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x^2+4.2x-24.5=0
a = 1; b = 4.2; c = -24.5;
Δ = b2-4ac
Δ = 4.22-4·1·(-24.5)
Δ = 115.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.2)-\sqrt{115.64}}{2*1}=\frac{-4.2-\sqrt{115.64}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.2)+\sqrt{115.64}}{2*1}=\frac{-4.2+\sqrt{115.64}}{2} $
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